symptoms of wrong tire size

I couldn't help but notice my post on this went unnoticed. Here's a quote from someone referring to an experiment conducted by Dodge on this topic. Note that with a wider tire, the contact patch of course got wider as well, but also LONGER... Overall patch area increased by even more than the width change would dictate by itself.

Quote--- "So lets go back to "Mechanics of pneumatic tires" perhaps they know what they are on about. In this book Prof Clark (Dept of Engineering Mechanics, Uni Michigan) talks about how the different constructions of a tyre will change the contact patch and how you cannot compare data from aircraft tyres with that of cars, tractors, trucks, bicycles etc. I thought it interesting that while a tyre with little external tread or shoulder region (i.e. aircraft/bicycle tyres) has a contact patch of an ellipse "for an automotive tyre a somewhat different set of relationships exists due to the fact that the usual construction involves the use of a relatively heavy tread, particularly in the shoulder region. In this case any significant contact spreads over the entire width of the tire between shoulders so that the contact area tends to have essentially straight parallel sides, and the width of this contact area is nominally independent of the tire deflection."

Thus for an automotive tyre the width of the contact patch is dependent in tyre width. However the length of the contact patch is dependent on tyre deflection, width and rolling radius. This was confirmed by experiments conducted by Dodge. They compared two 14 inch (26.7 inch diameter) tyres, one 7.5 inch wide and the other 8.0. The wider tyre consistently had a longer contact patch (not a huge increase mind you but a significant one) over a range of deflection values (0.5-2.0 inch). They then got the wide tyre and measured the contact patch length at a given deflection at three different pressures (15,24 & 30 psi) and the length was basically unchanged. They repeated this from 0.2-2.0 inches deflection at 0.2 inch intervals and got the same results. They then took the 8 inch wide tyres and increased the diameter to 28 and 30 inches. Again a small but significant increase in contact patch length occurred. "

---------- How much of this is due to structural stiffness is unknown to me, but note that even with extremely low (15psi) tire pressure the contact patch remained essentially constant at a given vertical deflection (of course the load was less). I only wish this fellow had posted the load numbers too. It would be interesting to see...

I'm not arguing with you Dave, just throwing something into the mix here. I don't know all about this yet and am experimenting right now with prediction models for this very thing, so hearing some input is just fine with me. However, it's not quite as clear cut as most people believe (yourself excluded).

Todd Wasson Racing Software

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J. Todd Wasson
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Just to throw a little more into the mix for everyone, here's an engineer's view on contact patch area and tire pressure. Note that he says the air gives rigidity to the tire, and that rigidity supports the weight (which follows my bulk modulus argument in the sci.physics thread). The air doesn't hold the weight according to this view.

Quote-

---------------------- "Bill Hussey wrote:

Not so. Heavy equipment uses HUGE bearings (the rollers that support our 8 million pound dragline are about 2' in diameter) because they spread the load over a much larger area than would rollers of the same length but a smaller diameter (imagine needle bearing rollers 1/8" in diameter but 3' long). The smaller rollers will lead to spalling (pitting) of the races and rollers because of the much higher contact stresses generated. Higher stress is due to smaller contact area.

A bicycle tire at 36 psi holding up 300 lbs does NOT flatten to that extent. (I should know, I can wheelie a bicycle rather well, and with a good-sized backpack of the sort that engineering students tend to carry, I can top 300 lbs.) The contact patch is nowhere near as large as the contact patch of my VFR. In order for the 1/2" wide bicycle tire contact patch to have the same area as the VFR contact patch (2.25" long, assume 2.25" diameter, therefore figure about 4 square inches), it would have to have a contact patch 4.5" long. Clearly it doesn't.

Remember, it's not simple hydraulic theory. The air gives rigidity to the tires, and the tires support the load. The air doesn't support the load itself.

Granted, different inflation pressures will give you different contact patch sizes. However, this is due to the fact that less pressure in the tire will give you less rigidity. The size of the contact patch does not have any sort of linear relationship with the inflation pressure. Physics, folks, physics. ;-)

By hydraulic theory, the area of the contact patch on my Land Cruiser (1100 lbs on each fron tire, tires aired down to 8 psi for off-road conditions) would have to be 138 square inches. Since I run tires that are 9.5" wide, the contact patch would have to be 14.5" long! Considering that this is very close to half the diameter of the tire, I think I would have noticed it by now. :-)

Dave Aley | mailto: snipped-for-privacy@cia-g.com DoD#454 Maintenance Mechanical Engineer | ASME #6363402 TLCA #8419 Lee Ranch Coal Company |

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New Mexico, USA ---------------------" Granted, a comparison with bicycle tires probably is not as valid, but his point with his Land Cruiser seems to back up this view.

Todd Wasson Racing Software

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Reply to
J. Todd Wasson

Hi Todd,

Yes I did note your post but given that the data is taken as a function of deflection and not load it isn't possible to draw any conclusions from it that would apply to the current debate. The wider tyres may well have required a larger load to obtain a given deflection at a given pressure and this would explain the longer contact patch. However that's pure speculation and without the load data we'll never know. Otherwise I don't see anything there that explicitly contradicts my post.

Dave Baker - Puma Race Engines

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"How's life Norm?" "Not for the squeamish, Coach" (Cheers, 1982)

Reply to
Dave Baker

Oh, ok. I understand. Thanks.

I'm curious, does this load over pressure equal the contact patch area then? I.e., instead of air pressure could you use bulk modulus (combination of air pressure and additional structural stiffness) and load to get the patch area within reason? But then it seems this would result in the same relation where you'd double the patch length by doubling the load.. Err... Maybe I need to read some more :-)

Todd Wasson Racing Software

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J. Todd Wasson

Yes, you're right of course.

I wish the guy had posted the load numbers to see how that works...

Todd Wasson Racing Software

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Reply to
J. Todd Wasson

It doesn't. It has 32 PSI pushing OUT, from the rim, in all directions.

You have four tires, each at 32 PSI. Does that mean the four tires can only support 128 pounds?

Read the excellent text at titles "How does 95 POUNDS support 5,400?"

Reply to
Clifton T. Sharp Jr.

Okay, here it is algebraically and exactly.

If four P205-75R14s have X square inches of contact patch, say four P215-75R14s would have X+N. If the car weighs L pounds, and it's sitting on X square inches, there's L/X pounds on every square inch of contact patch. Widen the tires, to L pounds on X+N square inches, and you now have L/(X+N) pounds per square inch of contact patch.

For all X greater than zero, and all N greater than zero, L/X is greater than L/(X+N). Therefore a wider tire will have fewer pounds per square inch of pressure on the contact patch than a narrower tire on the same car.

So when you roll over a three inch rock, and your contact patch is suddenly only two or three square inches, your tires autoinflate to several hundred PSI for that instant? Or maybe they explode every time? Or your car gets suddenly lighter?

Pressure inside the tire has nothing to do with the amount of pressure the tire exerts on other objects (e.g. the road). Pressure inside the tire only influences the shape of the tire as it presses on other things.

Reply to
Clifton T. Sharp Jr.

It doesn't. It has 32 PSI pushing OUT. You can prove the 32 PSI isn't pushing against the ground by lifting the tire off the ground and observing that it still has 32 PSI in it.

The pressure inside the tire only influences the shape of the tire as other things put external forces on it.

Reply to
Clifton T. Sharp Jr.

From experience: I put wider tires on my 1976 Torino. It lost grip. Thinking the model of tire made a difference, I put still wider tires of the same model on the car. It lost more grip. I finally put the manufacturer-recommended size of the same model tire on the car, and it got its grip back.

With the widest tires on the car, on snowy pavement I could not touch the accelerator at a standing stop without spinning the tires. The traction was so bad that I had to let off the brake and let the car get a rolling start before I could touch the accelerator. The tires would still spin if I did more than a slow, gradual acceleration from there.

Reducing contact pressure can never increase grip. Increasing pressure increases friction.

Reply to
Clifton T. Sharp Jr.

Food for thought...

To get the maximum contact patch area, racers use "slicks", tires with no tread at all and wide as the vehicle can stand. They have good grip off the line... but imagine how they'd be on cornering, wet pavement, snow/ice, and braking.

Reply to
Clifton T. Sharp Jr.

What a strange comment. A rubber molecule generates its grip equally in all directions. Slicks are used on race cars because they corner, brake AND grip under acceleration better. They don't just do the latter well and be crap at the first two. That's absurd.

Even if the argument were to be confined just to very specialised wrinkle wall drag slicks (which I suspect is all you have experience of) you can hardly improve grip off the line without the tyre working just as well under braking.

Dave Baker - Puma Race Engines

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"How's life Norm?" "Not for the squeamish, Coach" (Cheers, 1982)

Reply to
Dave Baker

What rubbish. You clearly don't have a clue. Decreasing the load on a tyre increases the coefficient of friction and therefore grip. Whether that's done by reducing weight or increasing tyre width and therefore contact patch area for a given weight the effect is the same. It's a cornerstone of race car chassis tuning and anyone who thinks otherwise shouldn't be sounding off in a technical thread. Exceptional cases like snow/mud/water have been covered in detail earlier on.

Dave Baker - Puma Race Engines

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"How's life Norm?" "Not for the squeamish, Coach" (Cheers, 1982)

Reply to
Dave Baker

"As an approximation, the number of square inches of footprint are is about equal to what you get when you divide the load by the inflation pressure. (It's not perfect, but it's close enough for our purposes.)"

Reply to
Stephen Bigelow

Do you know what PSI means?

Maybe you should too.

Quote from your source:

"As an approximation, the number of square inches of footprint are is about equal to what you get when you divide the load by the inflation pressure. (It's not perfect, but it's close enough for our purposes here.)"

Reply to
Stephen Bigelow

It's amazing you actually thought I didn't know this already... ;-)

Todd Wasson Racing Software

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Reply to
J. Todd Wasson

You're talking about snow? That's entirely different from dry pavement.

On snow or a wet surface, this is right. For dry pavement it is not. If you need some papers on experiments that verify this, let me know.

Todd Wasson Racing Software

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Reply to
J. Todd Wasson

Whoops, I spoke to soon in agreeing with you. The bit about cornering and braking is wrong. A tire will, for the most part, be capable of producing a given force in any direction. I've yet to see force data on a tire that shows it can produce more acceleration force than braking force. I won't go into why this occurs. The greatest deviation between forward/rearward and lateral force capability is about 20% at high loads. Most tires are much closer to the same in all directions.

As for cornering, I'll agree with Dave and say that's so far from the truth you should be evicted ;-)

Wrinkle wall drag tires are probably an exception in the cornering case because under lateral strain the contact patch might buckle and do other bizarre things, but I doubt anyone's measured this. Anyway, have a chat with someone that's driven road racing slicks through corners. Big grip...

You're right about the lousy grip on snow/ice with wider tires or slicks though.

BTW., when you switched to wider tires and lost grip, how much wider was the tread, exactly?

Todd Wasson Racing Software

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Reply to
J. Todd Wasson

Let's try an experiment. You'll need an 8"x10" sheet of sandpaper, a plastic cup and a brick.

Put the sandpaper rough side down on a flat surface. Apply lateral force only and push the sandpaper. Note it doesn't have much grip.

Put the plastic cup on top of the sandpaper. Apply lateral force only and push the sandpaper. Note it has more grip with the increased pressure from the plastic cup.

Remove the plastic cup and put the brick on top of the sandpaper. Apply lateral force only and push the sandpaper. Note it has a whole lot of grip with the increased pressure from the brick.

What did we just do? We gradually increased the pressure between the sheet of sandpaper and the flat surface, and as we did, we noticed that the sandpaper gripped the flat surface better every time we increased the pressure. With very little pressure we had very little grip; with slight pressure we had good grip; and with lots of pressure we had a whole lot of grip.

Document this, please.

Let's try another experiment. For this one you'll need a car and a strong jack.

First, we'll use the car with lots of weight on the drive wheels (the car's own weight). Start the car, put it in gear and punch it. Note the car goes with comparatively little tire slippage.

Now, return the car to the starting point. Engage the jack and lift the car until the tires on the drive wheels just touch the ground. Start the car, put it in gear and punch it. Note the vastly increased grip caused by the decreased load on the tire, which increased its coefficient of friction and therefore its grip.

You're obviously thinking only of the case of grip for the drive wheels on sudden application of torque. The cases of cornering and braking are vastly different.

Reply to
Clifton T. Sharp Jr.

I went up one size each tire change.

Reply to
Clifton T. Sharp Jr.

Then all that was happening was the suspension, tyre pressure or some other factor was preventing the bigger tyres working properly because set up right there's no way a wider tyre produces less dry grip than a narrow one.

Dave Baker - Puma Race Engines

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"How's life Norm?" "Not for the squeamish, Coach" (Cheers, 1982)

Reply to
Dave Baker

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