Just to throw a little more into the mix for everyone, here's an engineer's view on contact patch area and tire pressure. Note that he says the air gives rigidity to the tire, and that rigidity supports the weight (which follows my bulk modulus argument in the sci.physics thread). The air doesn't hold the weight according to this view.
Quote-
---------------------- "Bill Hussey wrote:
Not so. Heavy equipment uses HUGE bearings (the rollers that support our 8 million pound dragline are about 2' in diameter) because they spread the load over a much larger area than would rollers of the same length but a smaller diameter (imagine needle bearing rollers 1/8" in diameter but 3' long). The smaller rollers will lead to spalling (pitting) of the races and rollers because of the much higher contact stresses generated. Higher stress is due to smaller contact area.
A bicycle tire at 36 psi holding up 300 lbs does NOT flatten to that extent. (I should know, I can wheelie a bicycle rather well, and with a good-sized backpack of the sort that engineering students tend to carry, I can top 300 lbs.) The contact patch is nowhere near as large as the contact patch of my VFR. In order for the 1/2" wide bicycle tire contact patch to have the same area as the VFR contact patch (2.25" long, assume 2.25" diameter, therefore figure about 4 square inches), it would have to have a contact patch 4.5" long. Clearly it doesn't.
Remember, it's not simple hydraulic theory. The air gives rigidity to the tires, and the tires support the load. The air doesn't support the load itself.
Granted, different inflation pressures will give you different contact patch sizes. However, this is due to the fact that less pressure in the tire will give you less rigidity. The size of the contact patch does not have any sort of linear relationship with the inflation pressure. Physics, folks, physics. ;-)
By hydraulic theory, the area of the contact patch on my Land Cruiser (1100 lbs on each fron tire, tires aired down to 8 psi for off-road conditions) would have to be 138 square inches. Since I run tires that are 9.5" wide, the contact patch would have to be 14.5" long! Considering that this is very close to half the diameter of the tire, I think I would have noticed it by now. :-)
Dave Aley | mailto: snipped-for-privacy@cia-g.com DoD#454 Maintenance Mechanical Engineer | ASME #6363402 TLCA #8419 Lee Ranch Coal Company |
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