I'm in the process of removing the oil pan from my '75 CJ5 258. I've read through my Chilton's and Haynes manual, but can't seem to find the Torque spec's for the oil pan retaining bolts. The spec's for the 4 cylinder is in the Chilton's, but not the Haynes. Please Help. Also, any recommendations for oil pumps on this engine?
Oil Pan bolts?
Jan 17, 2005
23 Replies
Paul Brogren ( snipped-for-privacy@msn.com) wrote on Monday 17 January 2005 02:15 pm:
From my '82 service manual, the 1/4" are 7 ft-lb, and the 5/16" are 11 ft-lb. Use a torque wrench that is calibrated in inch-lbs.
Yeah, I thought I'd need an inch pound wrench sooner or later. Thanks again for the advice. let me know about the high volume oil pumps vs. the standard ones. I need to order one in the next couple days.
My Haynes manual has them listed in foot pounds, not inch pounds and says the small 1/4" ones are 5 to 7 Foot lb. and the larger 5/16" ones are 10 to 13 foot lb.
That is on page 2C-5.
Mike
86/00 CJ7 Laredo, 33x9.5 BFG Muds, 'glass nose to tail in '00 88 Cherokee 235 BFG AT'sPaul Brogren wrote:
There are two specs, one for 1/4" screws and another for 5/16" screws.
The Set To spec is 7 ft lb for the 1/4, and 11 for the 5/16. The Service In Use spec is 5 to 9 and 9 to 13, respectively. All measurments are in foot pounds.
The spec for Oil Pressure is 13psi at 600 RPM and 37 to 75 psi from 1600 RPM and up. The max pressure is determined by a bypass valve, this pressure is capped at 75psi.
I am not sure that a high flow oil pump is beneficial unless you make other unknown changes to accomodate the increased flow/pressure. My inclination would be to get another stock pump.
I pulled this data from my Factory Service Manual, but I must give a caveat that the Oil Capacity is listed at 4 quarts, plus the filter. My 258 holds 6 quarts, including the filter, so I can not vouch for the accuracy of the information I have given. Having said that, If I was rebuilding my motor, I would use all of the information, and accept the idea that the oil capacity is shown incorrectly.
My '81 FSM has the same specs. But, how does one measure a foot pound spec with an inch pound torque wrench? If one was supposed to use an inch pound wrench, wouldn't the spec be 84 and 132 in lb, respectively? And, does an inch pound wrench go this high?
I might do this wrong, but I would use a foot pound wrench when the spec calls for foot pounds. The trouble I would run into is that my foot pound wrench goes so high that is might not be very accurate at these small numbers.
Okay, I got some pretty decent info today. I talked to one of senior mechanics that I know from our Public Works Fleet Maintenance dept. He said to do a visual pressure test. I agree it will take a keen eye, but he said once the bolts are just finger tight, turn each bolt just until one sees a very slight visual gasket pinch. He said it works great. You just have to barely see the gasket squish and you stop.
The conversion is just a matter of multiplying by 12, right?
I hate to ask stupid questions, but this is so simple that it must be more difficult. 12 inch pounds is 1 foot pound, right.
Do you need Loctite or what? With parts falling off all over the West, I like to think my oil pan will stay with me for the long haul. Having screws only tightened basically finger tight on something that can spell the end of a good day, or the start of a bad one, makes me nervous. Although, 7 ft lb is something that could be accomplished with a nut driver ...
inclination
"Jeff Strickland" wrote in news: snipped-for-privacy@ez2.net:
Torque equals lever arm times force. So, yes, the distance from rotational centerline would be a linear translation. 12 inches to 1 foot.
Dave
So what, if a hot rod loses a part, it is somewhere in the preceding 1/4 mile, and on asphalt. If I lose a part it could be anywhere, and it probably in the dirt.
I challenge you to look at my CJ and see if you can figure out where the damn leak is coming from! I have been searching for years and I can't find it. ;-o
It's better to ask and be safe!
I believe ft-lbs is a cross product (think multiplication). Therefore we have "feet" * "pounds". The general way to convert an arbitrary unit to another one (for the same property) is to multiply by the conversions you know until all the units you don't want cancel out.
feet * pounds inches inches * pounds ------------- * ------ => --------------- 1 feet 1
Then fill in the numbers :
7 feet * pounds 12 inches 84 inches * pounds --------------- * --------- => ------------------ 1 1 feet 1The calculator on this site agrees with me, so I think both of us got it right :-).
formatting link
HTH,
-D
The obvious answer is to multiply by 12 to convert feet to inches, but I had this nagging thought in the back of my mind that said 12 inch pounds isn't a foot pound. I don't know where this thought came from, or why I am carrying it around, but I needed to get it verified.
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